Szakasz hosszának megállapítása
Author: zsuzsa@geogebra.org

 \sqrt{ (x_A-x_B)²+(y_A-y_B)² }

A = (6, -3)
B = (3, 3)
AB = Segment(A, B)
a = Segment(B, (x(B), y(A)))
b = Segment(A, (x(B), y(A)))
szh: AB + ""
szkmo: " \sqrt{ ((" + (x(A)) + ")-(" + (x(B)) + "))²+((" + (y(A)) + ")-(" + (y(B)) + "))² }= \sqrt{ (" + (x(A) - x(B)) + ")²+(" + (y(A) - y(B)) + ")² }= \sqrt{" + ((x(A) - x(B))^(2.0)) + "+" + ((y(A) - y(B))^(2.0)) + " } = \sqrt{" + ((x(A) - x(B))^(2.0) + (y(A) - y(B))^(2.0)) + " }= " + (sqrt((x(A) - x(B))^(2.0) + (y(A) - y(B))^(2.0)))